Easier method (and correct) to calculate Midsommardagen.

svn: r14165

src/plugins/lib/holidays.xml

@@ -411,7 +411,7 @@
     <date name="Första Maj" value="*/5/1" type="secular" />
     <date name="Kristi Himmelfärdsdag" type="religious" value="> easter(y)" offset="+39" />
     <date name="Nationaldag" value="*/6/6" type="secular" />
-    <date name="Midsommardagen" value="> swedish_midsummer_day(y)" type="religious" />
+    <date name="Midsommardagen" value="*/jun/20" offset="sat" type="religious" />
     <date name="Allahelgonadagen" value="*/1/sat/nov" type="religious" />
     <date name="Juldagen" value="*/12/25" type="religious" />
     <date name="Annandag Jul" value="*/12/26" type="religious" />

src/plugins/lib/libholiday.py

@@ -87,21 +87,6 @@ def dst(year, area="us"):
         stop =  "%d/%d/%d" % (year, 10, (31 - (math.floor(year * 5 / 4) + 1) % 7)) # Oct
     return (start, stop)
 
-def swedish_midsummer_day(year):
-    """
-    Function for calculating date for Swedish Midsummer Day
-    It is Saturday in week number 25, which is the third or
-    forth Saturday in June.
-    First possible date for third Saturday is June, 15
-    Last possible date for fourth Saturday is June, 28
-    In holidays.xml it is called by
-    <date name="Midsommardagen" value="> swedish_midsummer_day(y)" type="religious" />
-    """
-    for day in range(15,29):
-        d = datetime.date(year, 6, day)
-        if (year, 25, 6) == d.isocalendar():
-            return str(year) + "/6/" + str(day)
-
 #------------------------------------------------------------------------
 #
 # HolidayTable