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misc: fix ps etime tests

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The test assumes only one process appears which, depending on the
speed of things, may not be true. It now matches one to many process
lines.
This commit is contained in:
Craig Small 2018-04-10 22:09:40 +10:00
parent 0e39102f75
commit 5d8746b941
1 changed files with 1 additions and 1 deletions
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testsuite/ps.test/ps_output.exp
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@ -25,7 +25,7 @@ set flag_match {
"%cpu,pcpu,%mem,pmem" "%CPU\\s+%CPU\\s+%MEM\\s+%MEM\\s+\(\\d+\.\\d+\\s*\){4}$" "%cpu,pcpu,%mem,pmem" "%CPU\\s+%CPU\\s+%MEM\\s+%MEM\\s+\(\\d+\.\\d+\\s*\){4}$"
"blocked,sig_block,sigmask,caught,sigcatch,sig_catch" "\(BLOCKED\\s+\){3}\(CAUGHT\\s+\){2}CATCHED\\s+\(<?\[0-9a-f\]+\\s*\){6}$" "blocked,sig_block,sigmask,caught,sigcatch,sig_catch" "\(BLOCKED\\s+\){3}\(CAUGHT\\s+\){2}CATCHED\\s+\(<?\[0-9a-f\]+\\s*\){6}$"
"bsdstart,start,lstart" "\\s*START\\s+STARTED\\s+STARTED\\s+\(\\s*\(\[A-Z\]\[a-z\]{2} \\d+|\\d+:\\d{2}\)\\s+\(\[A-Z\]\[a-z\]{2} \\d+|\\d+:\\d{2}:\\d{2}\)\\s+\[A-Z\]\[a-z\]{2} \[A-Z\]\[a-z\]{2}\\s+\\d+ \\d{2}:\\d{2}:\\d{2} \\d{4}\\s*\)+$" "bsdstart,start,lstart" "\\s*START\\s+STARTED\\s+STARTED\\s+\(\\s*\(\[A-Z\]\[a-z\]{2} \\d+|\\d+:\\d{2}\)\\s+\(\[A-Z\]\[a-z\]{2} \\d+|\\d+:\\d{2}:\\d{2}\)\\s+\[A-Z\]\[a-z\]{2} \[A-Z\]\[a-z\]{2}\\s+\\d+ \\d{2}:\\d{2}:\\d{2} \\d{4}\\s*\)+$"
"bsdtime,cputime,etime,etimes" "\\s*TIME\\s+TIME\\s+ELAPSED\\s+ELAPSED\\s*\(\\s*\\d+:\\d{2}\\s+\\d{2}:\\d{2}:\\d{2}\\s+\(\\d{2}:\)?\\d{2}:\\d{2}\\s+\\d+\\s*\)$" "bsdtime,cputime,etime,etimes" "\\s*TIME\\s+TIME\\s+ELAPSED\\s+ELAPSED\\s*\(\\s*\\d+:\\d{2}\\s+\\d{2}:\\d{2}:\\d{2}\\s+\(\\d{2}:\)?\\d{2}:\\d{2}\\s+\\d+\\s*\)+$"
"user,ruser,group,rgroup,uid,ruid,gid,rgid" "\\s*USER\\s+RUSER\\s+GROUP\\s+RGROUP\\s+UID\\s+RUID\\s+GID\\s+RGID\\s+\(\(\\s*\[A-Za-z0-9_+-\]+\\s+\){4}\(\\d+\\s+\){4}\\s*\)+$" "user,ruser,group,rgroup,uid,ruid,gid,rgid" "\\s*USER\\s+RUSER\\s+GROUP\\s+RGROUP\\s+UID\\s+RUID\\s+GID\\s+RGID\\s+\(\(\\s*\[A-Za-z0-9_+-\]+\\s+\){4}\(\\d+\\s+\){4}\\s*\)+$"
"cputimes,times" "\\s*TIME\\s+TIME\\s+\\d+\\s+\\d+\\s*" "cputimes,times" "\\s*TIME\\s+TIME\\s+\\d+\\s+\\d+\\s*"
} }