Assume STDC_HEADERS will always be defined
We're in 2021. C89 is everywhere; in fact, there are many other assumptions in the code that wouldn't probably hold on pre-standard C environments. Let's simplify and assume that C89 is available. The specific assumptions are that: - <string.h>, and <stdlib.h> are available - strchr(3), strrchr(3), and strtok(3) are available - isalpha(3), isspace(3), isdigit(3), and isupper(3) are available I think we can safely assume we have all of those. Signed-off-by: Alejandro Colomar <alx.manpages@gmail.com>
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@ -38,7 +38,6 @@ dnl Checks for libraries.
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dnl Checks for header files.
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dnl Checks for header files.
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AC_HEADER_DIRENT
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AC_HEADER_DIRENT
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AC_HEADER_STDC
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AC_HEADER_SYS_WAIT
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AC_HEADER_SYS_WAIT
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AC_HEADER_STDBOOL
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AC_HEADER_STDBOOL
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@ -61,16 +61,8 @@ extern char * textdomain (const char * domainname);
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#endif
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#endif
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#endif
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#endif
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#if STDC_HEADERS
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#include <stdlib.h>
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#include <stdlib.h>
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#include <string.h>
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#include <string.h>
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#else /* not STDC_HEADERS */
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# ifndef HAVE_STRCHR
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# define strchr index
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# define strrchr rindex
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# endif
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char *strchr (), *strrchr (), *strtok ();
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#endif /* not STDC_HEADERS */
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#if HAVE_ERRNO_H
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#if HAVE_ERRNO_H
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# include <errno.h>
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# include <errno.h>
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@ -31,11 +31,7 @@
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#include <ctype.h>
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#include <ctype.h>
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#include <time.h>
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#include <time.h>
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#if defined (STDC_HEADERS) || (!defined (isascii) && !defined (HAVE_ISASCII))
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#define IN_CTYPE_DOMAIN(c) 1
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#define IN_CTYPE_DOMAIN(c) 1
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#else
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# define IN_CTYPE_DOMAIN(c) isascii(c)
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#endif
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#define ISSPACE(c) (IN_CTYPE_DOMAIN (c) && isspace (c))
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#define ISSPACE(c) (IN_CTYPE_DOMAIN (c) && isspace (c))
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#define ISALPHA(c) (IN_CTYPE_DOMAIN (c) && isalpha (c))
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#define ISALPHA(c) (IN_CTYPE_DOMAIN (c) && isalpha (c))
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@ -54,9 +50,7 @@
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#include "getdate.h"
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#include "getdate.h"
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#if defined (STDC_HEADERS)
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#include <string.h>
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#include <string.h>
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#endif
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/* Some old versions of bison generate parsers that use bcopy.
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/* Some old versions of bison generate parsers that use bcopy.
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That loses on systems that don't provide the function, so we have
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That loses on systems that don't provide the function, so we have
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