f93cf255d4
Closes #238 Update all files to list SPDX license shortname. Most files are BSD 3 clause license. The exceptions are: serge@sl ~/src/shadow$ git grep SPDX-License | grep -v BSD-3-Clause contrib/atudel:# SPDX-License-Identifier: BSD-4-Clause lib/tcbfuncs.c: * SPDX-License-Identifier: 0BSD libmisc/salt.c: * SPDX-License-Identifier: Unlicense src/login_nopam.c: * SPDX-License-Identifier: Unlicense src/nologin.c: * SPDX-License-Identifier: BSD-2-Clause src/vipw.c: * SPDX-License-Identifier: GPL-2.0-or-later Signed-off-by: Serge Hallyn <serge@hallyn.com>
83 lines
2.1 KiB
C
83 lines
2.1 KiB
C
/*
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* SPDX-FileCopyrightText: 1989 - 1993, Julianne Frances Haugh
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* SPDX-FileCopyrightText: 1996 - 1999, Marek Michałkiewicz
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* SPDX-FileCopyrightText: 2003 - 2005, Tomasz Kłoczko
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* SPDX-FileCopyrightText: 2007 - 2008, Nicolas François
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*
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* SPDX-License-Identifier: BSD-3-Clause
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*/
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#include <config.h>
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#ident "$Id$"
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#include <sys/types.h>
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#include <stdio.h>
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#include "prototypes.h"
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#include "defines.h"
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#include <pwd.h>
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/*
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* valid - compare encrypted passwords
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*
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* Valid() compares the DES encrypted password from the password file
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* against the password which the user has entered after it has been
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* encrypted using the same salt as the original. Entries which do
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* not have a password file entry have a NULL pw_name field and this
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* is used to indicate that a dummy salt must be used to encrypt the
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* password anyway.
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*/
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bool valid (const char *password, const struct passwd *ent)
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{
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const char *encrypted;
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/*@observer@*/const char *salt;
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/*
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* Start with blank or empty password entries. Always encrypt
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* a password if no such user exists. Only if the ID exists and
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* the password is really empty do you return quickly. This
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* routine is meant to waste CPU time.
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*/
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if ((NULL != ent->pw_name) && ('\0' == ent->pw_passwd[0])) {
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if ('\0' == password[0]) {
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return true; /* user entered nothing */
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} else {
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return false; /* user entered something! */
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}
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}
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/*
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* If there is no entry then we need a salt to use.
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*/
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if ((NULL == ent->pw_name) || ('\0' == ent->pw_passwd[0])) {
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salt = "xx";
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} else {
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salt = ent->pw_passwd;
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}
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/*
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* Now, perform the encryption using the salt from before on
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* the users input. Since we always encrypt the string, it
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* should be very difficult to determine if the user exists by
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* looking at execution time.
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*/
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encrypted = pw_encrypt (password, salt);
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/*
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* One last time we must deal with there being no password file
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* entry for the user. We use the pw_name == NULL idiom to
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* cause non-existent users to not be validated.
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*/
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if ( (NULL != ent->pw_name)
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&& (NULL != encrypted)
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&& (strcmp (encrypted, ent->pw_passwd) == 0)) {
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return true;
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} else {
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return false;
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}
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}
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